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SQL Query Complexity Estimator
SELECT u.id, u.name, COUNT(o.id) AS total_orders FROM users u LEFT JOIN orders o ON u.id = o.user_id WHERE u.status = 'active' GROUP BY u.id, u.name ORDER BY total_orders DESC;
Complexity Score
0
Risk Level
-
JOINs
0
Subqueries
0
Aggregates
0
Estimated Cost
0
Complexity Breakdown
Query Quality Radar
Complexity Score
